Calculating Amount of Reactant Needed
On this screen you will see how to calculate the minimum amount of a reactant to use to produce a specified amount of a product.
Consider the following reaction:
CH3COOH + C2H5OH ---------» «--------- CH3COOC2H5 + H20
You need to produce 44 grams of Ethyl Ethanoate. If Ethanol is present in excess, what is the MINIMUM amount of Ethanoic Acid in grams that you must use, assuming a percentage yield of 100 %. Answer to 1 decimal place.
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You need at least 30.0 grams of Ethanoic Acid.
Find the number of moles of Ethyl Ethanoate that you need to make.
Moles of Ethyl Ethanoate = Mass/RMM = 44/88.0 = 0.5 moles RMM = 88.0
Find how many moles of Ethanoic Acid are needed.
From the balanced equation you can see that to make:
1 mole of Ethyl Ethanoate requires 1 mole of Ethanoic Acid.
Thus to make:
0.5 moles of Ethyl Ethanoate requires 0.5 moles of Ethanoic Acid.
Thus to make:
0.5 moles of Ethyl Ethanoate requires 0.5 moles of Ethanoic Acid.
Find the mass of Ethanoic Acid needed.
0.5 moles of Ethanoic Acid are needed. Thus:
Mass of Ethanoic Acid needed = Moles x RMM
Mass of Ethanoic Acid needed = 0.5 x 60.0 g = 30.0 g
At least 30.0 grams of Ethanoic Acid are needed.
Mass of Ethanoic Acid needed = Moles x RMM
Mass of Ethanoic Acid needed = 0.5 x 60.0 g = 30.0 g
At least 30.0 grams of Ethanoic Acid are needed.
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