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Question 1 of 3

A powder contains a total of 5.6 moles of components. If the mole fraction of Sucrose is 0.652, how many moles of Sucrose are there to 4 decimal places?

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moles
There are 3.6512 moles of Sucrose present.

Moles of A = Mole Fraction of A x Total Number of Moles

Moles of Sucrose = 0.652 x 5.6 moles
Moles of Sucrose = 3.65120 = 3.6512 moles to 4 dec pl

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Question 2 of 3

A solution is made from Potassium Chloride and water only. If the mole fraction of Potassium Chloride is 0.006 and there are 22 moles of water present, how many moles of Potassium Chloride are there to 3 decimal places?

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moles
There are 0.133 moles of Potassium Chloride present.

Moles of A = Mole Fraction of A   x    Total Number of Moles

Moles of KCl = Mole Fraction of KCl x (Moles of KCl + Moles of Water)
Moles of KCl =        0.006        x        (Moles of KCl + 22)
Moles of KCl = 0.006 (Moles of KCl) + 0.132
Moles of KCl (1 - 0.006) = 0.132
Moles of KCl = 0.132
0.994
Moles of KCl = 0.1327 = 0.133 moles to 3 dec pl

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Question 3 of 3

A solution contains a total of 17 moles of components. If the mole fraction of Succinic Acid is 0.175, how many moles of Succinic Acid are there to 3 decimal places?

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moles
There are 2.975 moles of Succinic Acid.

Moles of A = Mole Fraction of A x Total Number of Moles

Moles of Succinic Acid = 0.175 x 17 moles

Moles of Succinic Acid = 2.9750 = 2.975 moles to 3 dec pl

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