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Question 1 of 3

There are 3.6 g of Codeine Phosphate in Codeine Linctus BP 1988 containing 0.3 % w/v Codeine Phosphate. Up to what volume - in litres - was the Linctus made?

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litres
The Linctus was made up to 1.2 litres.
EITHER
 volume of the product = mass of solute x     100     ml
% w/v
Volume of Codeine Linctus = 3.6 x    100    ml
0.3
Volume of Codeine Linctus = 1200 ml = 1.2 litres
OR
 0.3 % w/v means that there are
0.3 g Codeine Phosphate in 100 ml of Linctus
Thus: 3.6 g Codeine Phosphate are in    3.6    x 100 ml of Linctus
0.3
3.6 g Codeine Phosphate are in 1200 ml = 1.2 litres of Linctus

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Question 2 of 3

A Kaolin Mixture BP 1988 contains 20 % w/v Light Kaolin. If 90 g of Kaolin are used, up to what volume is the mixture made?

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ml
The Mixture is made up to 450 ml.
EITHER
 volume of the product = mass of solute x     100     ml
% w/v
Volume of Kaolin Mixture = 90 x    100    ml
20
Volume of Kaolin Mixture = 450 ml
OR
 20 % w/v means that there are
20 g Light Kaolin in 100 ml of Mixture
Thus: 90 g Light Kaolin is in    90    x 100 ml of Mixture
20
90 g Light Kaolin is in 450 ml of Kaolin Mixture

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Question 3 of 3

Up to what volume - in litres - should Methadone Linctus be made if 600 mg of Methadone Hydrochloride are present in Methadone Linctus BP 1988 containing 0.04 % w/v Methadone Hydrochloride?

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litres
The Linctus should be made up to 1.5 litres.
EITHER
Convert the mass of Methadone Hydrochloride to grams: 600 mg = 0.6 g
volume of the product = mass of solute x     100     ml
% w/v
Volume of Methadone Linctus = 0.6 x    100    ml
0.04
Volume of Methadone Linctus = 1500 ml = 1.5 litres
OR
 0.04 % w/v means that there are
0.04 g Methadone Hydrochloride in 100 ml of Linctus
Thus: 0.6 g Methadone Hydrochloride are in    0.6    x 100 ml of Linctus
0.04
0.6 g Methadone Hydrochloride are in 1500 ml = 1.5 litres of Methadone Linctus

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