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Question 1 of 3
A person gargles 15 ml of Compound Sodium Chloride Mouthwash BP 1988 containing 1.5 % w/v Sodium Chloride. How many milligrams of Sodium Chloride did the the person gargle with?
mass of solute = % w/v x volume of product g
100
mass of Sodium Chloride = 1.5 x 15 g
100
1.5 % w/v Sodium Chloride means that:
100 ml of mouthwash contains 1.5 g of Sodium Chloride
Thus: 15 ml of mouthwash contains 15 x 1.5 g of Sodium Chloride
100
15 ml of mouthwash contains 0.225 g ie 225 mg of Sodium Chloride
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Question 2 of 3
Methadone Linctus BP 1988 contains 0.04 % w/v Methadone Hydrochloride. 1.8 litres of the linctus needs to be prepared. How many grams of Methadone Hydrochloride need to be weighed out?
100
mass of Methadone Hydrochloride = 0.04 x 1800 g
100
0.04 % w/v Methadone Hydrochloride means that:
100 ml of linctus contains 0.04 g of Methadone Hydrochloride
Thus: 1800 ml of linctus contains 1800 x 0.04 g of Methadone Hydrochloride
100
1800 ml of linctus contains 0.72 g of Methadone Hydrochloride
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Question 3 of 3
A runner sprays 1.5 ml of Athlete's Foot Spray onto his foot. If the spray contains 1 % w/v Tolnaftate BP, how many milligrams of Tolnaftate did the runner spray onto his foot?
mass of solute = % w/v x volume of product g
100
mass of Tolnaftate = 1 x 1.5 g
100
1 % w/v Tolnaftate means that:
100 ml of spray contains 1 g of Tolnaftate
Thus: 1.5 ml of spray contains 1.5 x 1 g of Tolnaftate
100
1.5 ml of spray contains 0.015 g = 15 mg of Tolnaftate
No, that is not the correct answer.
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